<oai_dc:dc xmlns:oai_dc="http://www.openarchives.org/OAI/2.0/oai_dc/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.openarchives.org/OAI/2.0/oai_dc/ http://www.openarchives.org/OAI/2.0/oai_dc.xsd">
<dc:title>On the growth of powers of operators with spectrum contained in Cantor sets</dc:title>
<dc:creator>Cyril Agrafeuil</dc:creator>
<dc:subject>46J15</dc:subject><dc:subject>46J20</dc:subject><dc:subject>47A30</dc:subject><dc:subject>operators</dc:subject><dc:subject>Beurling algebra</dc:subject><dc:subject>spectral synthesis</dc:subject><dc:subject>perfect symmetric set</dc:subject>
<dc:description>For $\xi \in (0,\frac{1}{2})$, we denote by $E_{\xi}$ the perfect symmetric set associated to $\xi$, that is, $$E_{\xi} = \{\exp (2i\pi (1-\xi) \sum_{n=1}^{+\infty} \epsilon_{n} \xi^{n-1}) \epsilon_{n} = 0 \mbox{ or } 1\ (n \geq 1)\}.$$  Let $s$ be a nonnegative real number, and $T$ be an invertible bounded operator on a Banach space with spectrum included in $E_{\xi}$. We show that if \begin{align*}\|T^{n}\| &amp;= O(n^{s}),\quad n \to +\infty,\\ \|T^{-n}\| &amp;= O(e^{n^{\beta}}), \quad n \to +\infty\end{align*} for some $\beta &lt; \frac{\log(1/\xi) - \log2}{2log(1/\xi) - \log2}$, then for every $\varepsilon &gt; 0$, $T$ satisfies the stronger property $$\|T^{-n}\| = O(n^{s+1/2+\varepsilon}), \quad n \to +\infty.$$  This result is a particular case of a more general result concerning operators with spectrum satisfying some geometrical conditions.</dc:description>
<dc:publisher>Indiana University Mathematics Journal</dc:publisher>
<dc:date>2005</dc:date>
<dc:type>text</dc:type>
<dc:format>pdf</dc:format>
<dc:identifier>10.1512/iumj.2005.54.2657</dc:identifier>
<dc:source>10.1512/iumj.2005.54.2657</dc:source>
<dc:language>en</dc:language>
<dc:relation>Indiana Univ. Math. J. 54 (2005) 1473 - 1482</dc:relation>
<dc:coverage>state-of-the-art mathematics</dc:coverage>
<dc:rights>http://iumj.org/access/</dc:rights>
</oai_dc:dc>